2m²+m=32m²+m-3=0(2m+3)(m-1)=0m1=-3/2m2=1
2m^2+m-3=0(m-1)(2m+3)=0m=1、m=-3/2
解：2m^2+m=32m^2+m-3=0(2m+3)(m-1)=02m+3=0或m-1=0m=-3/2或m=1
