过抛物线y 2 =2px焦点的直线交抛物线于A、B两点,O为坐标原点,则 OA ? OB

2025-06-25 09:40:14
推荐回答(1个)
回答1:

若直线l垂直于x轴,则 A(
p
2
,p)
B(
p
2
,-p)
.
OA
?
OB
= (
p
2
) 2 - p 2 =-
3
4
p 2
.…(2分)
若直线l不垂直于轴,设其方程为 y=k(x-
p
2
)
,A(x 1 ,y 1 )B(x 2 ,y 2 ).
y=k(x-
p
2
)
y 2 =2px
? k 2 x 2 -p(2+ k 2 )x+
p 2
4
k 2 =0

x 1 + x 2 =
(2+ k 2 )
k 2
p, x 1 ? x 2 =
p 2
4
.…(4分)
OA
?
OB
=x 1 x 2 +y 1 y 2 = x 1 x 2 + k 2 ( x 1 -
p
2
)( x 2 -
p
2
)
= (1+ k 2 ) x 1 x 2 -
p
2
k 2 ( x 1 + x 2 )+
p 2 k 2
4
= (1+ k 2 )
p 2
4
-
p
2
k 2 ?
(2+ k 2 )p
k 2
+
p 2 k 2
4
=-
3
4
p 2

综上,
OA
?
OB
= -
3
4
p 2
为定值.…(6分)
故选B.