设t=2x-1 则x=(t+1)/2g(2x-1)=f(x)g(t)=f((t+1)/2)=((t+1)/2)^2+((t+1)/2)-1=(1/4)t^2+t-(1/4)所以 g(x)=(1/4)x^2+x-(1/4)希望能帮到你！
令2x-1=t,则x=(t+1)/2g(t)=f(x)=x²+x-1=(t+1)²/4+(t+1)/2-1=t²/4+t-1/4所以g(x)=x²/4+x-1/4
