已知2x-y-2的平方根是±6,2x+y-1的算术平方根是5,求2x-3y+11的平方根。大神们帮帮忙

2025-06-29 10:34:46
推荐回答(2个)
回答1:

由题可得,2X-Y-2=(±6)^2=36,2X+Y-1=5^2=25, 联立以上二式可解得,2X=32,Y=-6 所以2X-3Y+11=32-3*(-6)+11=61,则所求值为±√61

回答2:

2x+y-1=25 2x-y-2=36 4x=64 2x=32 -2y=12 -3y=18 2x-3y+11=32+18+11=61 2x-3y+11的平方根s是±√61