x2+(2m-3)x+m2=0设二个根分别是a,ba+b=-(2m-3)=3-2mab=m^2又1/a+1/b=1即a+b=ab3-2m=m^2m^2+2m-3=0(m+3)(m-1)=0m=-3或1(1)m=-3时,方程是x^2-9x+9=0,方程有解,符合.(2)m=1时,方程是x^2-x+1=0,方程无解,舍.综上所述,m=-3
