化简:1、sin40°(tan10°—根号3)2、tan70°cos10°(根号3tan20°—1)3、sin0°(1+根号3tan10°)

2025-06-25 15:00:22
推荐回答(1个)
回答1:

1.sin40°(tan10°-根号3)
=sin40*sin10/cos10-根号3*sin40
=sin40*cos80/cos10-根号3*sin40
=sin40*cos80/2sin40*cos40-根号3*sin40
=(1/2)*cos80/cos40-根号3*sin40
=[(1/2)*cos80-根号3sin40*sin40]/cos40
=[(1/2)cos80-根号3/2*sin80]/cos40
=(sin30*cos80-cos30*sin80)/cos40
=sin(30-80)/cos40
=-sin50/cos40
=-1 2.tan70×cos10×(√3tan20-1) =tan70×cos10×(tan60×tan20-1) =tan70×cos10×[(sin60×sin20/cos60×cos20)-1] =tan70×cos10×(sin60×sin20-cos60×cos20)/(cos60×cos20) =tan70×cos10×[-cos(60+20)]/(cos60 ×cos20) =-tan70×cos10×cos80/(cos60×cos20) =-tan70×cos10×sin10/(cos60×cos20) =-(sin70/cos70)×(1/2)×sin20/(cos60×cos20) =-(cos20/sin20)×sin20/(2cos60×cos20) =-1/(2cos60) =-1 第三个LZ打错了吧 sin0?? 3.sin50°(1+根号3tan10°)
= sin50°(cos10°+根号3sin10°) / cos10°
= sin50° * 2(cos60°cos10°+sin60°sin10°) / cos10°
= sin50° * 2 cos(60°-10°) / cos10°
= 2 sin50°cos50° / cos10°
= sin100° / cos10°
= sin(180°-80°) / cos10°
= sin80° / cos10°
= sin(90°-10°) / cos10°
= cos10° / cos10°
=1 这三道题应该叫求值 哈哈