(1)∵AB、AC的垂直平分线分别交BC于D、E,垂足分别是M、N,∴AD=BD,AE=CE,∵△ADE的周长是10,∴AD+DE+AE=BD+DE+CE=BC=10,即BC=10.(2)∵∠BAC=100゜,∴∠B+∠C=180°-∠BAC=80°,∵AD=BD,AE=CE,∴∠BAD=∠B,∠CAE=∠C,∴∠BAD+∠CAE=80°,∴∠DAE=∠BAC-(∠BAD+∠CAE)=100°-80°=20°.