limx趋近于0slnx^2⼀xcosx的极限

2025-06-28 07:14:37
推荐回答(1个)
回答1:

lim(x->0)sin(x^2)/(xcosx) (0/0)
=lim(x->0)2xcos(x^2)/(-xsinx+cosx)
=0