python 判断是否有连续数字

s_list=['25','24','23','02','04','06','08','22','23','24','25','02','04','06','08','23','24','25']#要判断的字符型数字,如果纯粹是数字的话后把int删了就行
end_list=[]#结果列表
t_len=len(s_list)
z=0
for i in range(1,t_len,1):
if (int(s_list[i])-int(s_list[i-1]))==1:
if z<=0:
if z<-1:
argtemp=[]
for j in range(i z-1,i,1):
argtemp.append(s_list[j])
end_list.append(argtemp)
z=1
else:
z=z 1
elif (int(s_list[i])-int(s_list[i-1]))==-1:
if z>=0:
if z>1:
argtemp=[]
for j in range(i-z-1,i,1):
argtemp.append(s_list[j])
end_list.append(argtemp)
z=-1
else:
z=z-1
else:
z=abs(z)
if z>1:
argtemp=[]
for j in range(i-z-1,i,1):
argtemp.append(s_list[j])
end_list.append(argtemp)
z=0
z=abs(z)
if z>1:
argtemp=[]
for j in range(t_len-z-1,t_len,1):
argtemp.append(s_list[j])
end_list.append(argtemp)
for argtemp in end_list:
for t in argtemp[:-1]:
print t,
print argtemp[-1]
#结果
#25 24 23
#22 23 24 25
#23 24 25

遍历加正则