解方程:①x눀-5x-6=0 ②(x눀-10)눀+3x눀=28

求详细解答过程,谢谢各位
2025-06-27 12:45:54
推荐回答(1个)
回答1:

x²-5x-6=0
(x-6)(x+1)=0
x1=6,x2=-1

(x²-10)²+3x²=28
设x²=t

(t-10)²+3t=28
t²-20t+100+3t=28
t²-17t+72=0
(t-8)(t-9)=0
t1=8,x1=-2√2,x2=2√2
t2=9,x3=3,x4=-3