已知方程组{3x+y=1 x-2y=m,若方程组的解满足x>y,求m的取值范围.

2025-06-28 23:02:55
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回答1:

3x+y=1---(1)
x-2y=m---(2)
(1)×2得6x+2y=2---(3)
(3)+(2)得
7x=m+2
x=(m+2)/7
(2)×3得
3x-6y=3m----(4)
(1)-(4)得
7y=1-3m
y=(1-3m)/7
x>y
(m+2)/7>(1-3m)/7
m+2>1-3m
4m>-1
m>-1/4