已知:x+y=1,xy=-1⼀2,求:(x+y)的平方(x-y)+2y的平方(x+y)的值

RT 急求
2025-06-27 23:03:48
推荐回答(1个)
回答1:

x+y=1,xy=-1/2

(x+y)^2(x-y)+2y^2(x+y)
=(x+y)[(x+y)(x-y)+2y^2]
=(x+y)[x^2-y^2+2y^2]
=(x+y)[x^2+y^2]
=(x+y)[(x+y)^2-2xy]
=1*[1^2-2*(-1/2)]
=1+1
=2