根据勾股定理:斜边=√(3²+2.4²)=√14.76=0.6√41米所以:3米直角边对角=ArcSin[3/(0.6√41)]≈51.34°2.4米直角边对角=ArcSin[2.4/(0.6√41)]≈38.66° 或直接≈90°-51.34°=38.66°
设直角三角形ABC,〈A=90度,〈B对边为3米,〈C对边为2.4米,用正切函数解之,tanB=3/2.4=1.25,B=51°20',C=90°-51°20'=38°40'..