(1)
S1=1/4(a1+1)^2=a1
a1^2-2a1+1=0
(a1-1)^2=0
a1=1
S2=1/4(a2+1)^2=a1+a2
a2^2-2a2+1=4a1=4
a2^2-2a2-3=0
(a2+1)(a2-3)=0
a2=-1或3
因为an>0,所以a2=3
(2)
an=2n-1
(3)
bn=20-an=20-2n+1=21-2n
b1=19
和Tn=n(b1+bn)/2=n(19+21-2n)/2=n(20-n)
=-(n-10)^2+100
当bn=10时,和最大,为100
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