f(x)=a^x ＋ log(a) (x+1),当a>1时，函数f(x)是增函数，所以最小值是f(0),最大值是f(1),则有f(0)+ f(1)=a,即[1+ log(a)1]+[a+ log(a)2]=a,log(a)2=-1，所以a=1/2.因为a>1，所以a=1/2舍去。当0则有f(0)+ f(1)=a,即[1+ log(a)1]+[a+ log(a)2]=a,log(a)2=-1，所以a=1/2.经检验a=1/2符合题意。综上可知a=1/2.
