求X^2-Y^2-2Y-1因式分解?

2025-06-29 10:49:59
推荐回答(5个)
回答1:

解法为:x^2-(y+1)^2=(x+y+1)(x-y-1)

回答2:

x^2 -(y+1)^2
=(x+y+1)(x-y-1)

回答3:

X^2-Y^2-2Y-1
=x^2-(y^2+2y+1)
=x^2-(y+1)^2
=(x+y+1)(x-y-1)

回答4:

x^2-(y+1)^2=(x+y+1)(x-y-1)

回答5:

(x+y)(x-y)-(2y+1)