在三角形ABC中,角B=45度,角C=30度,AB=8根号2,BC=8+8根号3,求AC?

2025-06-28 06:21:13
推荐回答(2个)
回答1:

a/sinA=b/sinB=c/sinC
A=180°-B-C=105°
a/sinA=b/sinB
b=asinB/sinA
=(8+8√3)*(√2/2)/(√6+√2)/4
=(4√2+4√6)*4/(√6+√2)
=16

回答2:

16,正弦定理ac/sinB=ab/sinC