一道概率论与数理统计证明题

2025-06-27 11:30:28
推荐回答(1个)
回答1:

解:
E(X)=p
D(X)=p(1-p)
D(X拔)=D(X)/n=p(1-p)/n
E(X拔)=E(x)=p
E(X拔²)=D(X拔)+E(X拔)²=p(1-p)/n+p²
E(S²)=σ²=D(x)=p(1-p)
E(p)=E(X拔²)-E(S²/n)=p(1-p)/n+p²-p(1-p)/n=p²
无偏得证
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