f(x)=sin^4x-cos^4x的周期为

2025-06-29 00:46:14
推荐回答(1个)
回答1:

f(x)=sin^4x-cos^4x
=(sin²x-cos²x)(sin²x+cos²x)
=sin²x-cos²x
=-cos2x
∴ f(x)=sin^4x-cos^4x的周期为2π/2=π.