(Ⅰ)由题意可得a2.j=a1.j+1,故有 a2.8 =a1.7+a2.7 =a1.7+a1.7+1=2×26+1=129.
故答案为 129.
(Ⅱ)由题意可得b1=3,b2=5,当n≥3时,bn=2n-2+1+bn-1,即 bn-bn-1=2n-2+1.
由 b1=3,b2-b1=2,b3-b2=2+1,b4-b3=22+1,b5-b4=23+1,b6-b5=24+1,…bn-bn-1=2n-2+1,
累加可得 bn=3+2+(2+1)+(22+1)+(23+1)+(24+1)+…+(2n-2+1)
=5+(2+22+23+…+2n-2)+(n-2)×1=
+n+3=2n-1+n+1,2(1?2n?2) 1?2
故答案为 bn=2n-1+n+1.