lim(x→0)[(1⼀x^2)-(1⼀xsinx)] 求极限,

2025-06-24 22:38:10
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回答1:

1/x^2-1/xsinx=(sinx-x)/x^2*sinx分子分母求导数(cosx-1)/(2xsinx+x^2*cosx)还是0/0分子分母求导数-sinx/(2sinx+2xcosx+2xcosx-x^2*sinx)在求导-cosx/(2cosx+4cosx-4xsinx-2xsinx-x^2*cosx)x→0=-1/(2+4...