若x,y满足(x^2)+(2*(y^2))-2*x*y-2*y+1=0, 求x,y的值

2025-06-26 01:31:44
推荐回答(1个)
回答1:

x²-2xy+y²+y²-2y+1=0
(x-y)²+(y-1)²=0
∴x-y=0
y-1=0
∴x=1
y=1