代数问题

已知14(x^2+y^2+z^2)=(x+2y+3z)^2求x:y:z多谢!
2025-06-27 22:58:05
推荐回答(1个)
回答1:

14(x^2+y^2+z^2)=(x+2y+3z)^2
14x^2+14y^2+14z^2=x^2+4y^2+9z^2+2xy+3xz+2xy+6yz+3xz+6yz
13x^2+10y^2+5z^2-4xy-6xz-12yz=0
4x^2-4xy+y^2+9x^2-6xz+z^2+9y^2-12yz+4z^2=0
(2x-y)^2+(3x-z)^2+(3y-2z)^2=0
2x=y, x:y=1:2
3x=z, x:z=1:3
3y=2z, y:z=2:3

x:y:z=1:2:3