求微分方程dx⼀y+dy⼀x=0满足初始条件y(4)=2特解的为?

2025-06-28 07:24:10
推荐回答(1个)
回答1:

dx/y+dy/x = 0 , 2xdx+2ydy = 0, x^2+y^2 = C ,
y(4) = 2 代入得 C = 20 , 特解 x^2+y^2 = 20