设i为虚数单位,则复数i⼀2+i等于

2025-06-27 17:29:12
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回答1:

i/2+i=(1/2+1)i=3/2i
i/(2+i)
=i(2-i)/[(2+i)(2-i)]
=(2i+1)/(4+1)
=(2i+1)/5