x+ 1 2 -1 2 x+1 1 -1 1 x+1初等变换r1+r2得x +3 x+3 0 2 x+1 1 -1 1 x+1在第一行用代数余子式求得(x+3)[(x+1)^2-1]-(x+3)[2(x+1)+1]=(x+3){[(x+1)-1]^...
