不等式log以2为底(x+1⼀x+6)<=3的解集? 谢谢

2025-06-27 11:38:38
推荐回答(1个)
回答1:

x+1/x+6<=2^3=8
x+1/x-2<=0
(x^2-2x+1)/x<=0
而x≠1时,x^2-2x+1>0,x=1时,x^2-2x+1=0
x<0或x=1

另:x+1/x+6>0
(x^2+6x+1)/x>0
x=1时满足
x<0时,x^2+6x+1<0
-3-2√2解集为(-3-2√2,-3+2√2)∪{1}