已知abc=1,求a⼀(ab+a+1)+b⼀(bc+b+1)+c⼀(ca+c+1)

2025-06-29 08:19:59
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回答1:

abc=1
a/(ab+a+1)+b/(bc+b+1)+c/(ca+c+1)=a/(ab+a+1)+ab/(abc+ab+a)+abc/(caab+abc+ab)
=a/(ab+a+1)+ab/(1+ab+a)+1/(a+1+ab)
=(a+ab+1)/(ab+a+1)=1